http://poj.org/problem?id=3009DescriptionOn Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat ...
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其他好文 时间:
2014-09-20 01:04:46
阅读次数:
279
在Keepalived集群中,其实并没有严格意义上的主、备节点,虽然可以在Keepalived配置文件中设置“state”选项为“MASTER”状态,但是这并不意味着此节点一直就是Master角色。控制节点角色的是Keepalived配置文件中的“priority”值,但并它并不控制所有节点的角色,...
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其他好文 时间:
2014-09-19 17:29:35
阅读次数:
226
本来想用 priority_queue 去写个bfs。结果重载运算符忘了。ORZ。
然后看书和问别人熟悉了一下,记录一下。
struct lx
{
int x,y,lv;
};
有一个这样的结构体。x,y,是坐标,lv 是它的权。重载
struct lx
{
int x,y,lv;
friend bool operator<(lx a,lx b)
...
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编程语言 时间:
2014-09-19 12:01:05
阅读次数:
236
Priority Queue
Definition & Description:
In computer
science/data structures, a priority queue is
an abstract data type which
is like a regular queue or stack data
str...
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其他好文 时间:
2014-09-19 03:25:45
阅读次数:
301
当时想到了贪心,但是不知为何举出了反列。。。。我是逗比,看了点击打开链接。才发现我是逗比。
Problem Description
There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:
● ai ∈ [0,n]
●...
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其他好文 时间:
2014-09-16 02:44:19
阅读次数:
276
Problem Description
There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:
● ai ∈ [0,n]
● ai ≠ aj( i ≠ j )
For sequence a and sequence b,...
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其他好文 时间:
2014-09-15 21:22:10
阅读次数:
240
如上图中的2,用4位二进制(总共4层)来表示,同时总共出现2次。即共需要位数为2*4,实际上反应在哈佛曼树中,即为在每层都加上2,总共加了4次(4即为2的层数,从最底层一直到19,19不算),因此将除最顶层19除外,将树种所有的数总加起来,即为每个数总共需要的位数。关于priority_queuer...
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其他好文 时间:
2014-09-15 17:27:39
阅读次数:
152
在查看了ubuntu的debian rules,重新配置chromium
GYP_GENERATORS=make GYP_DEFINES="disable_sse2=1 use_third_party_translations=1 werror= sysroot= disable_nacl=1 linux_use_gold_binary=0 linux_use_gold_flags=0 enab...
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其他好文 时间:
2014-09-15 14:23:38
阅读次数:
231
Problem Description
There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:
● ai ∈ [0,n]
● ai ≠ aj( i ≠ j )
For sequence a and sequence b,...
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其他好文 时间:
2014-09-15 01:06:27
阅读次数:
175
Problem Description
There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:
● ai ∈ [0,n]
● ai ≠ aj( i ≠ j )
For sequence a and sequence b, t...
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其他好文 时间:
2014-09-14 23:41:28
阅读次数:
262