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spoj cot: Count on a tree 主席树
10628. Count on a treeProblem code: COTYou are given a tree with N nodes.The tree nodes are numbered from 1 to N.Each node has an integer weight.We wi...
分类:其他好文   时间:2014-07-27 10:31:42    阅读次数:304
【leetcode刷题笔记】Text Justification
Given an array of words and a lengthL, format the text such that each line has exactlyLcharacters and is fully (left and right) justified.You should p...
分类:其他好文   时间:2014-07-27 10:05:32    阅读次数:352
Ext.js form 表单提交问题
var form = new Ext.form.FormPanel({ labelAlign : 'right', border : false, bodyStyle : 'background-color: transpar...
分类:Web程序   时间:2014-07-27 09:48:22    阅读次数:291
POJ - 1679 The Unique MST (次小生成树)
Description Given a connected undirected graph, tell if its minimum spanning tree is unique. Definition 1 (Spanning Tree): Consider a connected, undirected graph G = (V, E). A spanning tree of...
分类:其他好文   时间:2014-07-26 17:19:22    阅读次数:401
HDU 1556 - Color the ball
原理就是先利用两个数间的差分,因为把一段连续的数做标记相当于头差分+1,尾差分-1,然后做前缀和即可。可以想到,相比segment tree这种个只适合于查询操作不多但修改操作很多的情况(如果保存前缀和修改又会降速),否则计算前缀和会很费时。/*ID:esxgx1LANG:C++PROG:hdu15...
分类:其他好文   时间:2014-07-26 17:05:31    阅读次数:233
LeetCode "Populating Next Right Pointers in Each Node II"
Compared with I version, the tree could be incomplete. The only difference is that, we connect current node's child to next non-childrenless' node's f...
分类:其他好文   时间:2014-07-26 17:02:11    阅读次数:316
Jump Game Two
class Solution { public: const int MAXVALUE = 1 << 30; int findMinStepToIndex(int maxNumbers[],int maxSteps,int index) { if (index == 0) return 0; int left = 1; int right = maxSteps;...
分类:其他好文   时间:2014-07-26 15:30:01    阅读次数:170
POJ - 3013 Big Christmas Tree
Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas tree. The simple structure of the tree is shown in right picture. The tree can ...
分类:其他好文   时间:2014-07-26 15:01:50    阅读次数:300
[LeetCode] Binary Tree Level Order Traversal
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).For example: Given binary tree {3...
分类:其他好文   时间:2014-07-26 14:03:16    阅读次数:174
SPOJ QTREE系列 树上分治问题。
375.Query on a tree 【QTREE】 有两个操作: (1)修改第i条边的边权 (2)询问a到b路径上的边权最大值。 树链剖分入门题。树链剖分+线段树维护最大值。修改/查询均为O(log^2)。 很懒,没有写。913.Query on a tree II 【QTREE2...
分类:其他好文   时间:2014-07-26 13:53:45    阅读次数:569
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