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day2_chapter4_标准类型和内建函数
1. 标准类型 Integer,Boolean, Long integer, Floating point real number, Complex number, String, List, Tuple, Dictionary 其他内建类型: 类型, Null对象(None) 文件,集合,函数.....
分类:其他好文   时间:2014-05-10 00:20:30    阅读次数:336
orable常用语句
1.for循环语句:for loop_counter in [REVERSE] lowest_number .. highest_numberloop {.statements.}end loop;示例:declare v_i number(4) := 0;begin for v_i in 0...
分类:其他好文   时间:2014-05-10 00:19:58    阅读次数:396
Highly divisible triangular number
我的那个暴力求解,太耗时间了。用了网上产的什么因式分解,质因数之类的。确实快!还是数学基础不行,只能知道大约。The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangl...
分类:其他好文   时间:2014-05-09 23:43:16    阅读次数:342
不带查询条件的分页
SELECT * FROM ( SELECT ROW_NUMBER() OVER(ORDER BY ca.PraiseNum desc) as RowID ,ca.[ArticleId] ...
分类:其他好文   时间:2014-05-09 13:17:14    阅读次数:409
As3 计算两个日期之间的天数差
/*日期转YYYYMMDD*/formDate.fullYear+""+(formDate.month _fromYear){manyAllDayNum = Number(alreadyOverDay(fromFormatDayStr)[1]) + Number(alreadyOverDay(toF...
分类:其他好文   时间:2014-05-09 12:56:06    阅读次数:288
Twenproxy介绍
Twemproxy is a proxy server that allows you to reduce the number of open connections to yourMemcached or Redis server. What is Twemproxy useful for? It can reduce the number of connections t...
分类:其他好文   时间:2014-05-09 06:30:25    阅读次数:258
hdu 1711 Number Sequence 解题报告
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711题目意思:给出一条有n个数的序列a[1],a[2],......,a[n],和一条有m 个数的序列b[1],b[2],......,b[m],求出b[1],b[2],...,b[m]在序列a中完全匹...
分类:其他好文   时间:2014-05-09 05:53:04    阅读次数:268
some simple recursive lisp programs
1. Write a procedure count-list to count the number of elements in a list1 (defun count-list (numbers)2 (if (null numbers) 03 (+ 1 (co...
分类:其他好文   时间:2014-05-09 05:41:41    阅读次数:307
poj 1743 Musical Theme(男人八题&后缀数组第一题)
Musical Theme Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17298   Accepted: 5939 Description A musical melody is represented as a sequence of N (1<=N<=20...
分类:其他好文   时间:2014-05-09 02:46:57    阅读次数:375
HDU - 3415 Max Sum of Max-K-sub-sequence
题意:求长度不超过K的最大的连续序列的和 思路:采用单调队列,我们要求的是Max{sum[i]-sum[j]}(i-j#include #include #include #include using namespace std; const int MAXN = 1000005; const int INF = 0x3f3f3f3f; int n,k; int arr[MAXN],s...
分类:其他好文   时间:2014-05-09 01:57:07    阅读次数:264
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