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POJ - 2886 Who Gets the Most Candies? (反素数+线段树)
Description N children are sitting in a circle to play a game. The children are numbered from 1 to N in clockwise order. Each of them has a card with a non-zero integer on it in his/her hand. Th...
分类:其他好文   时间:2014-08-02 15:37:33    阅读次数:259
HDU 3652 B-number 数位DP
很裸,注意状态的记录和存储#include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std;...
分类:其他好文   时间:2014-08-02 15:24:13    阅读次数:236
[The network path was not found][0x80070035] 为何不能访问Windows共享?
安装了一个2008的VM,欢天喜地准备做一些测试,结果在用UNC访问VM的过程中出现了如下错误,这个错误其实非常普遍,在google里搜error number能搜出好多文章,这其实也是最可怕的地方,搜出来的东西千奇百怪,却没有一个能和自己的错误对应上。本例就是其中一个,windows firewa...
分类:Windows程序   时间:2014-08-02 15:23:53    阅读次数:1025
[数据库]ROW_NUMBER() OVER函数的基本用法
(1)ROW_NUMBER() OVER(ORDER BY COLUMN) 通常,开发者和管理员在一个查询里,用临时表和列相关的子查询来计算产生行号。现在SQL Server 2005提供了一个函数,代替所有多余的代码来产生行号。 简单的说row_number()从1开始,为每一条分组记录返回一个数字,这里的ROW_NUMBER() OVER (ORDER BY xlh DESC) 是...
分类:数据库   时间:2014-08-02 13:00:23    阅读次数:332
Codeforces Round #259 (Div. 1)——Little Pony and Expected Maximum
输入n、m,表示一个n面的色子(面上的值为1-n),投掷m次,求得到的最大值的期望(1?≤?m,?n?≤?105)....
分类:其他好文   时间:2014-08-02 12:57:13    阅读次数:189
B - Georgia and Bob
Description Georgia and Bob decide to play a self-invented game. They draw a row of grids on paper, number the grids from left to right by 1, 2, 3, ..., and place N chessmen on different grid...
分类:其他好文   时间:2014-08-02 12:56:13    阅读次数:312
Single Number II
Single Number II Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?...
分类:其他好文   时间:2014-08-02 12:53:53    阅读次数:289
Codeforces Round #259 (Div. 2) C - Little Pony and Expected Maximum
题目链接题意:分析: 1 #include 2 #include 3 #include 4 #include 5 #include 6 #include 7 #include 8 #define LL long long 9 using namespace std;10 11 int ...
分类:其他好文   时间:2014-08-02 12:43:43    阅读次数:217
退役笔记一#MySQL = lambda sql : sql + ' Source Code 4 Explain Plan '
Mysql 查询运行过程 大致分为4个阶段吧:语法分析(sql_parse.cc)>>sql_resolver.cc # JOIN.prepare生成逻辑查询plan(sql_optimizer.cc)>># JOIN.optimize生成物理查询plan(sql_planner.cc)run th...
分类:数据库   时间:2014-08-02 12:28:33    阅读次数:239
MSSQL 4表联查,子查询,函数统计,分组条件查询综合应用实例
1 SELECT 2 [UserName] 3 ,[Yhxm] 4 ,[Qx] 5 ,[Phone] 6 ,[Number] = COUNT([UserName]) 7 FROM 8 (SELECT 9 [UserName] = A.[username] 10 ,[Y...
分类:数据库   时间:2014-08-02 12:23:43    阅读次数:308
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