Quartz是OpenSymphony开源组织在Job scheduling领域又一个开源项目 思路:1.依赖 2.任务 3.配置文件 4.测试 1.依赖 2.任务类 3.配置文件 ...
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其他好文 时间：
2017-06-28 23:04:24
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230
一、ThreadPoolTaskExecutor配置<beanid="taskExecutor"class="org.springframework.scheduling.concurrent.ThreadPoolTaskExecutor">
<!--线程池维护线程的最少数量-->
<propertyname="corePoolSize"value="5"/>
<!--线程池维护线程所允许的空闲时间--&g..
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编程语言 时间：
2017-06-26 10:28:13
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198
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters fo ...
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其他好文 时间：
2017-06-25 10:00:59
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156
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Given a string, find the first non ...
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其他好文 时间：
2017-06-23 10:17:03
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132
/** * Disables the current thread for thread scheduling purposes unless the * permit is available. * * <p>If the permit is available then it is consum ...
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编程语言 时间：
2017-06-20 12:25:24
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281
Overview ... YARN Architecture The fundamental idea of YARN is to split up the functionalities of resource management and job scheduling/monitoring in ...
class Solution { public: int lengthOfLongestSubstring(string s) { int hashTable[255]; fill(hashTable, hashTable+255, -1); int start = 0, maxLen = 0; f... ...
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其他好文 时间：
2017-06-17 19:36:29
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106
Machine Schedule Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 13071 Accepted: 5575 Description As we all know, machine scheduling is a v ...
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系统相关 时间：
2017-06-16 21:14:21
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209
https://leetcode.com/problems/first-unique-character-in-a-string/#/description Given a string, find the first non-repeating character in it and return ...
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其他好文 时间：
2017-06-11 22:16:03
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139
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. ...
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其他好文 时间：
2017-06-11 10:11:16
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163
