第一节、B树、B+树、B*树 1.前言: 动态查找树主要有:二叉查找树(Binary Search Tree),平衡二叉查找树(Balanced Binary Search Tree),红黑树(Red-Black Tree ),B-tree/B+-tree/ B*-tree (B~Tree)。前三者... ...
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其他好文 时间:
2016-09-04 23:58:58
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1809: Parenthesis Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains ...
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2016-09-04 13:02:41
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原题链接 http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1809 Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions ...
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2016-09-04 00:08:09
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Balanced Lineup Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 47419 Accepted: 22270 Case Time Limit: 2000MS Description For the daily mil ...
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2016-09-03 18:23:13
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Problem G: Parenthesis Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P rem ...
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2016-09-03 18:00:36
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Description Bessie the cow is trying to type a balanced string of parentheses into her new laptop, but she is sufficiently clumsy (due to her large ho ...
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2016-09-02 08:46:27
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RMQ模板题 1 #include<cstdio> 2 #include<cstring> 3 using namespace std; 4 const int N=50001,M=30; 5 int n,q,h[N],minl[N][M],maxl[N][M]; 6 int RMQ(int,int ...
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2016-08-31 23:45:52
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Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 给出一个所有元素以升序排序的单链表,将它转换成一棵高度平衡的二分查找树 ...
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2016-08-29 12:36:11
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Balanced Number Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 4624 Accepted Submission(s): 217 ...
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2016-08-27 09:53:03
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Question:
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
把有序数组转化成平衡的BST
Algorithm:
找到数组中间的元素,作为根节点,则根节点左边是左子树,根节点右边是右子树,接着递归
Accepted Co...
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其他好文 时间:
2016-08-24 09:58:55
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