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iOS完整的证书配置
关于苹果iOS开发,有关于开发证书,生产证书,in_house证书,add_Hoc证书申请过程中的问题,以及上架发布问题非常重要。今天就着重说一下关于针对于苹果开发者网站更新之后的真机调试证书申请。 这所有的前提都是:你得有苹果开发者账号个人($99)、公司($99)、企业($299)账号均可。 工具/原料 能上网的苹果电脑 浏览器 Xcode 5...
分类:移动开发   时间:2016-04-29 15:31:17    阅读次数:270
[LintCode] House Robber II 打家劫舍之二
After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This t ...
分类:其他好文   时间:2016-04-29 14:30:43    阅读次数:122
[LintCode] House Robber 打家劫舍
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping yo ...
分类:其他好文   时间:2016-04-29 14:19:43    阅读次数:172
CQUOJ 10819 MUH and House of Cards
Polar bears Menshykov and Uslada from the zoo of St. Petersburg and elephant Horace from the zoo of Kiev decided to build a house of cards. For that t ...
分类:其他好文   时间:2016-04-24 18:42:43    阅读次数:193
leetcode 337. House Robber III
题目: The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each ...
分类:其他好文   时间:2016-04-22 16:20:50    阅读次数:145
【hdu5538】【2015ACM/ICPC亚洲区长春站 】House Building 题意&题解&代码
2015ACM/ICPC亚洲区长春站 模拟 水题...
分类:其他好文   时间:2016-04-21 11:50:50    阅读次数:188
Leetcode题目:House Robber
题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stoppin ...
分类:其他好文   时间:2016-04-20 21:52:34    阅读次数:124
198. House Robber
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping yo ...
分类:其他好文   时间:2016-04-17 10:19:50    阅读次数:135
hdu 5538 House Building(长春现场赛——水题)
题目链接:acm.hdu.edu.cn/showproblem.php?pid=5538 House Building Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 621    Accepted Submis...
分类:其他好文   时间:2016-04-16 19:17:01    阅读次数:241
LeetCode 337. House Robber III
一开始以为不直接连接的话就考虑隔层加钱,偶数层和奇数层分开算得两个结果,但是输入为[4,1,null,2,null,null,3]时最大值为4+3 = 7,4是第0层,3是3层。 因此要以节点为对象,而不是层。每个节点的情况分两种,抢和不抢,如果抢当前节点,那么左右节点不能抢;如果不抢,那么当前节点 ...
分类:其他好文   时间:2016-04-12 21:01:32    阅读次数:339
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