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Wildcard Matching leetcode java
题目:Implement wildcard pattern matching with support for '?' and '*'.'?' Matches any single character.'*' Matches any sequence of characters (includin....
分类:编程语言   时间:2014-08-06 04:10:50    阅读次数:325
Leetcode--Next Permutation
Problem Description: Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rea...
分类:其他好文   时间:2014-08-05 22:40:40    阅读次数:241
hdu 4704 Sum (费马小定理+快速幂)
//(2^n-1)%mod //费马小定理:a^n ≡ a^(n%(m-1)) * a^(m-1)≡ a^(n%(m-1)) (mod m) # include # include # include # define mod 1000000007 using namespace std; __int64 pow(__int64 n) { __int64 p=1,q=2; w...
分类:其他好文   时间:2014-08-05 22:40:30    阅读次数:242
Leetcode :: Single Number II
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without u...
分类:其他好文   时间:2014-08-05 22:35:00    阅读次数:277
【LeetCode】Pow(x, n)
Implement pow(x, n). 思路:快速幂运算,需要考虑指数为负数,同时底数为0的情况,这种属于异常数据,代码里没有体现。 class Solution { public: double pow_abs(double x, unsigned int n) { if (n == 0) { return 1;...
分类:其他好文   时间:2014-08-04 21:32:48    阅读次数:314
LeetCode: LRU Cache [146]
【题目】Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations:getandset.get(key)- Get the ...
分类:其他好文   时间:2014-08-04 21:10:27    阅读次数:218
140802暑期培训.txt
1、pow函数    #include    pow(x,y)用来计算以x 为底的 y 次方值,然后将结果返回。    注意:pow函数返回值为double型        printf ("32.01 ^ 1.54 = %f\n", pow (32.01, 1.54) );        (他也可以计算小数的小数次方) 2、动态规划:    动态规划过程是:每次决策依赖于当前状态,...
分类:其他好文   时间:2014-08-04 17:52:40    阅读次数:206
Streaming Video with RTSP and RTP
The Code In this lab you will implement a streaming video server and client that communicate using the Real-Time Streaming Protocol (RTSP) and send data using the Real-time Transfer Protocol (RTP). Y...
分类:其他好文   时间:2014-08-04 11:06:37    阅读次数:413
Java面向对象㈡ -- 继承与多态
Java的继承是通过extends和implement来实现的,Java不支持多继承,但是Java支持多层继承以及多实现(接口)。Java继承有一个关键字super是用来指向父类。Java继承衍生出覆盖的概念。覆盖被用来支持多态。实际开发中Java通常继承于抽象类,实现于接口。如果不希望一个类被继承...
分类:编程语言   时间:2014-08-02 20:44:13    阅读次数:219
Single Number II
Single Number II Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?...
分类:其他好文   时间:2014-08-02 12:53:53    阅读次数:289
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