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搜索关键字:digits    ( 2164个结果
93. Restore IP Addresses
问题描述: Given a string containing only digits, restore it by returning all possible valid IP address combinations. Example: Input: "25525511135" Output: ...
分类:其他好文   时间:2018-06-10 11:53:33    阅读次数:102
1136 A Delayed Palindrome (20)
Consider a positive integer N written in standard notation with k+1 digits a~i~ as a~k~...a~1~a~0~ with 0 <= a~i~ < 10 for all i and a~k~ > 0. Then N ...
分类:其他好文   时间:2018-06-09 23:20:40    阅读次数:199
1132 Cut Integer (20)
Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 1673 ...
分类:其他好文   时间:2018-06-09 23:17:22    阅读次数:212
1120 Friend Numbers (20)
Two integers are called "friend numbers" if they share the same sum of their digits, and the sum is their "friend ID". For example, 123 and 51 are fri ...
分类:其他好文   时间:2018-06-09 20:30:32    阅读次数:159
1069 The Black Hole of Numbers (20)
1069 The Black Hole of Numbers (20)(20 分) For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-inc ...
分类:其他好文   时间:2018-06-09 19:46:01    阅读次数:160
66. Plus One
Given a non-empty array of digits representing a non-negative integer, plus one to the integer. The digits are stored such that the most significant d ...
分类:其他好文   时间:2018-06-08 21:58:38    阅读次数:164
[LeetCode] Rotated Digits 旋转数字
X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotate ...
分类:其他好文   时间:2018-06-08 14:08:55    阅读次数:166
C++大数模板
#include <bits/stdc++.h> using namespace std; class DividedByZeroException {}; class BigInteger { private: vector<char> digits; bool sign; // true for ...
分类:编程语言   时间:2018-06-05 11:34:57    阅读次数:159
Android EditText 限制输入为ip类型
editText.setInputType(InputType.TYPE_CLASS_NUMBER); String digits = "0123456789."; editText.setKeyListener(DigitsKeyListener.getInstance(digits)); set ...
分类:移动开发   时间:2018-06-04 11:50:12    阅读次数:267
LeetCode 258. Add Digits
玩过极限脱出999,对数字根印象深刻。 随便一个数,假设abcd, abcd=a*1000+b*100+c*10+d =a*(1+999)+b*(1+99)+c*(1+9)+d =(a+b+c+d)+a*999+b*99+c*9 =(a+b+c+d)+9*(a*111+b*11+c) 所以abcd% ...
分类:其他好文   时间:2018-06-03 14:30:50    阅读次数:119
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