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各种语言lambda闭包
swift reversed = sorted(names, { (s1: String, s2: String) -> Bool in return s1 > s2 }) java8 list.sort((a, b) -> { Integer.compare(a.length(),b.length() }); C++ sort(x,x + N,[](float a, float b) { ...
分类:编程语言   时间:2015-06-09 17:54:47    阅读次数:138
把视频秒数转换成时间格式输出
functionsecondsToTime(time,forceHours){ varhours=Math.floor(time/3600)%24, minutes=Math.floor(time/60)%60, seconds=Math.floor(time%60), result=((forceHours||hours>0)?(hours<10?‘0‘+hours:hours)+‘:‘:‘‘)+(minutes<10?‘0‘+minutes:minutes)+‘:‘+(secon..
分类:其他好文   时间:2015-06-09 17:37:55    阅读次数:155
Leetcode题解(7)L51/N-Queens
L51: N-Queens   The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-qu...
分类:其他好文   时间:2015-06-09 17:32:04    阅读次数:140
java语言实现顺序表
public class SqList { private int[] data; private int length; public SqList() { data = new int[30]; length = 0; } public boolean empty() { return length == 0; } public int length() {...
分类:编程语言   时间:2015-06-09 17:29:11    阅读次数:145
leetcode_Factorial Trailing Zeroes_easy
Given an integer n, return the number of trailing zeroes in n!. Note: Your solution should be in logarithmic time complexity. 方法:找1...n中每个数因式分解中,5的个数(5的个数一般大于2的个数),即为10的个数 注意:题目要求时间复杂度:...
分类:其他好文   时间:2015-06-09 17:23:55    阅读次数:110
HDU 2191--DP--(多重背包)
题意:汶川地震买大米 分析:裸多重背包,这题数据比较小所以可以三重循环不需要优化 代码: #include #include using namespace std; int dp[1000][1000],t,n,m; int p[1000],h[1000],c[1000]; int max(int a,int b) { return a>b?a:b; } int main() { ci...
分类:其他好文   时间:2015-06-09 17:22:15    阅读次数:146
Leetcode[1]-Two Sum
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where in...
分类:其他好文   时间:2015-06-09 17:12:28    阅读次数:97
一些常用的JS函数
//获取元素属性function getStyle(obj, attr) { return obj.currentStyle ? obj.currentStyle[attr] : getComputedStyle(obj, 0)[attr];}//运动函数function doMove(obj, a...
分类:Web程序   时间:2015-06-09 16:52:24    阅读次数:133
Function类型-没有重载
没有重载 将函数名想象为指针,也有助于理解为什么ECMAScript中没有函数重载的概念。funcrion addSomeNumber(num){ return num+100; }function addSomeNumber(num){ return num+200; }var resu...
分类:其他好文   时间:2015-06-09 16:45:12    阅读次数:96
【Divided Two】cpp
题目:Divide two integers without using multiplication, division and mod operator.If it is overflow, return MAX_INT.代码:class Solution {public: int div...
分类:其他好文   时间:2015-06-09 16:31:20    阅读次数:97
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