for(Shop s:list) { System.out.println(s.getName()); String sql="select shopId,sum(ele_bank+ele_card+water_card+water_bank+coal_c...
分类：
其他好文 时间：
2015-05-21 01:21:35
阅读次数：
152
Vasya is the beginning mathematician. He decided to make an important contribution to the science and to become famous all over the world. But how can he do that if the most interesting facts such as P...
分类：
其他好文 时间：
2015-05-20 09:57:25
阅读次数：
97
Given one point P0 on a 2-dimension space.There are n other points on the same space.Try to find K points which are most closed to P0.hint: Part ofQu....
分类：
其他好文 时间：
2015-05-20 08:15:26
阅读次数：
138
DescriptionThe most important part of a GSM network is so called Base Transceiver Station (BTS). These transceivers form the areas called cells (this ...
分类：
其他好文 时间：
2015-05-19 16:17:59
阅读次数：
160
Make Interfaces Easy to Use Correctly and Hard to Use IncorrectlyScott MeyersONE OF THE MOST COMMON TASKS in software development is interface specification. Interfaces occur at the highest level of ab...
分类：
其他好文 时间：
2015-05-19 10:39:20
阅读次数：
102
public class Solution { public int maxArea(int[] height) { if (height == null || height.length < 2) { return 0; } ...
分类：
其他好文 时间：
2015-05-19 08:51:27
阅读次数：
125
Follow up for "Remove Duplicates":What if duplicates are allowed at most twice?For example,Given sorted array nums = [1,1,1,2,2,3],Your function shou....
分类：
编程语言 时间：
2015-05-19 00:46:34
阅读次数：
334
网址：https://leetcode.com/problems/container-with-most-water/
题意：
找两条纵深线,然后利用x坐标来计算容器面积.
分析：
先找最远的两头,然后往中间收缩,
长变小了,高变长才能使面积可能更大.
所以就是找更长的...
解法：
如果height[left]
反之,同理.
代码：
https://github.com/L...
分类：
其他好文 时间：
2015-05-18 16:43:02
阅读次数：
115
Title:Say you have an array for which theithelement is the price of a given stock on dayi.If you were only permitted to complete at most one transacti...
分类：
其他好文 时间：
2015-05-18 12:26:25
阅读次数：
114
1.先获取两段的垂线和x轴组成的容器可以容纳的水量tempSum，并使得maxSum=tempSum;
2.然后再去除两段较小的垂线段，组成新的容器，获得新的可容纳的水量tempSum，并更新maxSum
3.循环直至start==end...
分类：
其他好文 时间：
2015-05-18 10:54:03
阅读次数：
122
