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leetcode - Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get ...
分类:其他好文   时间:2014-11-19 14:13:08    阅读次数:149
LeetCode: Min Stack 解题报告
Min Stack My SubmissionsQuestionSolutionDesign a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Pu...
分类:其他好文   时间:2014-11-19 00:15:08    阅读次数:271
【leetcode】Min Stack -- python版
题目描述:Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Re...
分类:编程语言   时间:2014-11-18 23:14:32    阅读次数:198
自适应大屏
在清单中配置<supports-screensandroid:anyDensity="true"android:largeScreens="true"android:normalScreens="true"android:resizeable="true"android:smallScreens="true"android:xlargeScreens="true"/><application......./>
分类:其他好文   时间:2014-11-18 11:59:19    阅读次数:176
leetcode Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get ...
分类:其他好文   时间:2014-11-16 13:30:08    阅读次数:174
Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Remov...
分类:其他好文   时间:2014-11-15 23:12:56    阅读次数:193
于Linux-2.6.32内核上编译ipset-6.23的坎坷经历
新版本的ipset上周在儿童医院给小小看病等待叫号的间隙,收到了Netfilter邮件列表的推送消息,一览了ipset最新的6.23版本的新特性,很多正是我目前所需要的,特别是timeout和skbinfo参数的支持,具体的详情请自行查看manual,如果不想看那么多,我这里简单的贴一下:   timeout       All  set  types  supports the optional...
分类:系统相关   时间:2014-11-14 22:52:47    阅读次数:327
区别deque vector 和数组
Leetcode更新到155题了,这个easy的题acceptance却不高,我好奇的点开了它。Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(...
分类:编程语言   时间:2014-11-14 19:24:03    阅读次数:240
LeetCode——Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get ...
分类:其他好文   时间:2014-11-13 20:50:45    阅读次数:197
Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Removes...
分类:其他好文   时间:2014-11-13 18:07:10    阅读次数:212
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