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搜索关键字:the cows are journey    ( 1818个结果
Aggressive cows
描述 Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= ...
分类:其他好文   时间:2020-03-15 15:04:13    阅读次数:48
被kuangbin带着飞-最短路
A - Til the Cows Come Home POJ - 2387 板题; #include<cstdio> #include<vector> #include<queue> using namespace std; #define pb push_back typedef long lon ...
分类:其他好文   时间:2020-03-11 00:53:37    阅读次数:68
Poj机试 A Knight's Journey *BFS,存在问题
基本思想: 有一个大坑,就是字典序的问题; 还有一个就是代码简洁度的问题; 关键点: 无; #include<iostream> #include<vector> #include<string> using namespace std; const int maxn = 30; int p, q; ...
分类:其他好文   时间:2020-03-08 21:47:45    阅读次数:64
Journey Planning
Tanya wants to go on a journey across the cities of Berland. There are nn cities situated along the main railroad line of Berland, and these cities ar ...
分类:其他好文   时间:2020-03-07 16:19:18    阅读次数:74
B. Journey Planning
Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) B. Journey Planning time limit per test 2 seconds memory limit per test 256 megaby ...
分类:其他好文   时间:2020-03-02 13:13:48    阅读次数:68
Codeforces Round #625
"A Journey Planning" 题意: 有一列共 n 个城市, 每个城市有美丽值b[i], 要访问一个子序列的城市, 这个子序列相邻项的原项数之差等于美丽值之差, 求最大的美丽值总和. 思路: 对于一个合法的子序列, b[i] i 结果是一个定值, 统计该值取最大. view code i ...
分类:其他好文   时间:2020-03-02 00:58:32    阅读次数:75
Cleaning Shifts / OpenJ_Bailian - 2376
Farmer John is assigning some of his N (1 <= N <= 25,000) cows to do some cleaning chores around the barn. He always wants to have one cow working on ...
分类:其他好文   时间:2020-03-01 12:50:46    阅读次数:80
【POJ - 3186】Treats for the Cows (区间dp)
Treats for the Cows 先搬中文 Descriptions: 给你n个数字v(1),v(2),...,v(n-1),v(n),每次你可以取出最左端的数字或者取出最右端的数字,一共取n次取完。假设你第i次取的数字是x,你可以获得i*x的价值。你需要规划取数顺序,使获得的总价值之和最大。 ...
分类:其他好文   时间:2020-02-26 19:15:13    阅读次数:65
JavaScript数组常用API方法汇总
1、push() 方法将一个或多个元素添加到数组的末尾,并返回该数组的新长度。 const animals = ['pigs', 'goats', 'sheep']; const count = animals.push('cows'); console.log(count); // expecte ...
分类:编程语言   时间:2020-02-25 11:14:01    阅读次数:81
线段树(单点修改,区间求和,区间最大)
(一)线段树 1.E - Lost Cows N (2 <= N <= 8,000) cows have unique brands in the range 1..N. In a spectacular display of poor judgment, they visited the neig ...
分类:其他好文   时间:2020-02-25 00:34:58    阅读次数:174
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