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Codeforces Round #129 (Div. 2) A
Description The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil"). However, Rozdil is dangerous to settle, so ...
分类:其他好文   时间:2016-07-30 13:32:36    阅读次数:147
React loves you — 洞悉Redux装的逼
你若装逼,请带我飞! 从前,从前,听说React只负责UI,话说写Angular代码就像写后端,现在看来,React赢在情怀上了; 我认为没必要老是拿React和Angular做比较,Angular是一套大而全的相对完备的框架;而React确实是只负责UI,只是多出很多概念层的东西,需要自己以此去构 ...
分类:其他好文   时间:2016-07-25 01:38:10    阅读次数:183
O - Can you find it?(二分法)
Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, ...
分类:其他好文   时间:2016-07-23 14:58:57    阅读次数:154
codeforces 691E Xor-sequences(矩阵快速幂)
引自:http://www.cnblogs.com/shuguangzw/p/5674089.html ...
分类:其他好文   时间:2016-07-22 23:00:24    阅读次数:294
O - Can you find it?
Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, ...
分类:其他好文   时间:2016-07-22 21:00:45    阅读次数:164
CSU-ACM2016暑假集训训练1-二分搜索 A - Can you find it?
Time Limit:3000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64u Description Give you three sequences of numbers A, B, C, then we give you a numbe ...
分类:其他好文   时间:2016-07-21 17:57:14    阅读次数:234
187. Repeated DNA Sequences
建一个set, 是曾经遇到过的长度为10的string,然后对这个sample string从头到尾走一遍,如果曾经看到,那么就加到repeated set里,最后返回由repeated string组成的arrayList<String>里面。 之所以repeated也需要一个自己的set,因为有 ...
分类:其他好文   时间:2016-07-21 06:22:29    阅读次数:127
Dylans loves numbers
Problem Description Who is Dylans?You can find his ID in UOJ and Codeforces. His another ID is s1451900 in BestCoder.And now today's problems are all ...
分类:其他好文   时间:2016-07-19 23:31:33    阅读次数:335
CodeForces 558 C. Amr and Chemistry && 51NOD 1483 化学变换(暴力 + 贪心)
传送门 Amr loves Chemistry, and specially doing experiments. He is preparing for a new interesting experiment.Amr has n different types of chemicals. Each chemical i has an initial volume of ai liters. F...
分类:其他好文   时间:2016-07-15 20:54:01    阅读次数:467
codeforces 691E Xor-sequences 矩阵快速幂
思路:刚开始 n个元素,a[i][j]代表以i开头,j结尾的二元组符合条件的有多少 这是等于长度为2的数量 长度为3的数量为a*a,所以长度为n的数量是a^(k-1) 然后就是矩阵快速幂,然而我并不能发现这道题是矩阵快速幂,没办法,太弱了 注:这个模板是从Q神的AC代码里扒下来的,仰慕Q神 #inc ...
分类:其他好文   时间:2016-07-15 17:11:15    阅读次数:140
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