Box2对象的构造函数.用来在二维空间内创建一个二维矩形边界边界对象.Box2对象的功能函数采用
定义构造的函数原型对象来实现.
NOTE:如果没有参数min,max将二维矩形边界初始化为Infinity,无穷大
three.js 源码注释(十一)Math/Box2.js
用法: var min = new Vector2(0,0),max = new Vector2(1,1); var box = new Box2(min,max);
通过两个Vector2(二维向量)min,max创建一个二维矩...
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Web程序 时间:
2014-11-15 15:33:44
阅读次数:
317
Given an array of integers, every element appearstwiceexcept for one. Find that single one.Note:Your algorithm should have a linear runtime complexity...
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其他好文 时间:
2014-11-15 11:18:50
阅读次数:
137
Given an array of integers, every element appearsthreetimes except for one. Find that single one.Note:Your algorithm should have a linear runtime comp...
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其他好文 时间:
2014-11-14 22:44:04
阅读次数:
231
Given two sorted integer arrays A and B, merge B into A as one sorted array.Note:You may assume that A has enough space (size that is greater or equal...
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其他好文 时间:
2014-11-14 09:15:31
阅读次数:
143
Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
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其他好文 时间:
2014-11-13 23:47:53
阅读次数:
177
Given an indexk, return thekthrow of the Pascal's triangle.For example, givenk= 3,Return[1,3,3,1].Note:Could you optimize your algorithm to use onlyO(...
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其他好文 时间:
2014-11-13 18:32:04
阅读次数:
183
如有错漏请不吝拍砖指正,转载请注明出处,很感谢 桌面便签软件是android上经常使用软件的一种,比方比較早的Sticky Note,就曾很流行,Sticky Note的介绍能够參见 http://www.tompda.com/c/article/11778/而实际上使用android平台对widg...
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移动开发 时间:
2014-11-13 16:16:16
阅读次数:
251
Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complex...
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其他好文 时间:
2014-11-13 16:03:20
阅读次数:
139
Given a collection of integers that might contain duplicates,S, return all possible subsets.Note:Elements in a subset must be in non-descending order....
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其他好文 时间:
2014-11-13 09:24:37
阅读次数:
148
Given a set of distinct integers,S, return all possible subsets.Note:Elements in a subset must be in non-descending order.The solution set must not co...
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其他好文 时间:
2014-11-13 09:19:23
阅读次数:
220