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[Android] 触屏setOnTouchListener实现图片缩放、移动、绘制和添加水印
本文主要讲述使用触屏实现图片缩放、移动、添加水印等功能,所以该篇文章主要通过setOnTouchListener监听实现该功能,如何使用RelativeLayout进行布局,MotionEvent.ACTION_DOWN:表明视图已经接收一次触摸,按下时触发、MotionEvent.ACTION_UP:表明视图停止接受一次触摸,被放开时触发、MotionEvent.ACTION_POINTER_DOWN:当屏幕上已经有一点被按住,再按下其他点时触发同时希望文章对大家有所帮助.protected void o...
分类:移动开发   时间:2014-10-28 20:11:31    阅读次数:284
os 计算机的启动
零、boot的含义先问一个问题,”启动”用英语怎么说?回答是boot。可是,boot原来的意思是靴子,”启动”与靴子有什么关系呢? 原来,这里的boot是bootstrap(鞋带)的缩写,它来自一句谚语:"pull oneself up by one's bootstraps"字面意思是”拽着鞋带把...
分类:其他好文   时间:2014-10-28 13:38:24    阅读次数:213
Python web develop - 1 set up environment
搭建开发环境首先,确认系统安装的Python版本是2.7.x:$ python --versionPython 2.7.5然后,安装开发Web App需要的第三方库:前端模板引擎jinja2:$ sudo apt-get install python-jinja*有python-jinja2 和py...
分类:编程语言   时间:2014-10-28 10:20:36    阅读次数:231
leetcode Path Sum
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.Fo...
分类:其他好文   时间:2014-10-28 07:02:27    阅读次数:171
[leetcode]Binary Tree Level Order Traversal II
问题描述: Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree {3,9,20,#,#,...
分类:其他好文   时间:2014-10-27 21:21:00    阅读次数:190
detecting locked tables mysql (locked by LOCK TABLE)
detecting locked tables mysql (locked by LOCK TABLE)up vote15down votefavorite7I would like to know whether there is an option to detect locked tables...
分类:数据库   时间:2014-10-27 21:09:44    阅读次数:307
Elevator
Problem DescriptionThe highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at wh...
分类:其他好文   时间:2014-10-27 17:29:51    阅读次数:170
[Django] Setting up Django Development Environment in Ubuntu 14.04
1. PythonOf course you will need Python. Still Python 2.7 is preferred, however if you would like to create new projects with Python 3, it is also fin...
分类:系统相关   时间:2014-10-27 14:19:53    阅读次数:283
DIV_ROUND_UP(x,y)实现x/y向上取整
#define DIV_ROUND_UP(x,y) (((x) + ((y) - 1)) / (y))1、问题 x、y都是整数,且x > 1, y > 1,求 x / y的向上取整,即: 当 x / y整除时,向上取整值为 x / y; 当x / y不整除时,向上取整值为(x / y) + 1...
分类:其他好文   时间:2014-10-27 14:17:24    阅读次数:307
[LeetCode] TwoSum
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two nu...
分类:其他好文   时间:2014-10-26 21:10:30    阅读次数:170
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