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搜索关键字:digit recongnizer    ( 1477个结果
[?*]Letter Combinations of a Phone Number
Given a digit string, return all possible letter combinations that the number could represent.A mapping of digit to letters (just like on the telephon...
分类:其他好文   时间:2015-11-17 08:24:43    阅读次数:199
poj 1684 Lazy Math Instructor(字符串)
题目链接:http://poj.org/problem?id=1686思路分析:该问题为表达式求值问题,对于字母使用浮点数替换即可,因为输入中的数字只能是单个digit。代码如下:#include #include #include #include #include #include using ...
分类:其他好文   时间:2015-11-17 00:12:38    阅读次数:224
POJ2680(动态规划,大数)
Computer TransformationTime Limit:1000MSMemory Limit:65536KTotal Submissions:4548Accepted:1731DescriptionA sequence consisting of one digit, the numbe...
分类:其他好文   时间:2015-11-16 19:30:15    阅读次数:126
BASH系列(3)—— BASH通配符和正则表达式
BASH中的通配符(wildcard)*:任意长度的任意字符。 ?:任意单个字符 []:匹配范围 [^]:排除匹配范围 [:alnum:][:alpha:][:blank:][:cntrl:] [:digit:][:graph:][:lower:][:print:] [:punct:][:space:][:upper:][:xdigit:]正则表达式.:表示匹配任意单个字符。 *:表示匹配前..
分类:其他好文   时间:2015-11-09 19:11:14    阅读次数:206
[LeetCode]67. Number of Digit One1的个数和
Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.For example:Given n = 13,Return 6...
分类:其他好文   时间:2015-11-09 12:33:27    阅读次数:136
[LeetCode] Add Digits
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.For example:Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, r...
分类:其他好文   时间:2015-11-08 19:29:06    阅读次数:231
[LeetCode]64. Add Digits数根
Given a non-negative integernum, repeatedly add all its digits until the result has only one digit.For example:Givennum = 38, the process is like:3 + ...
分类:其他好文   时间:2015-11-08 14:30:48    阅读次数:226
PHP一些验证字符串的函数
ctype_alnum— 检查字符串中只包含数字或字母,相当于正则[A-Za-z0-9].ctype_alpha— 检查字符串中只包含字母。ctype_cntrl— 检查字符串中是否只包含" '\n' '\r' '\t' " 这样的控制字符。ctype_digit— 检查字符串中是否只包含数字。ct...
分类:Web程序   时间:2015-11-05 18:45:55    阅读次数:180
LeetCode Integer to English Words
原题链接在这里:https://leetcode.com/problems/integer-to-english-words/没三个digit分成一个 unit, 用unitNumber 函数把这三位数换算成数字加上对应的unit.Note: num = 1,000,000时不可以出现 "One M...
分类:其他好文   时间:2015-11-05 06:06:15    阅读次数:157
LintCode "Permutation Index II" !
Simply a variation to "Permutation Index". When calculating current digit index, we consider duplicated case.Again, similar as "Digit Counts", it is a...
分类:其他好文   时间:2015-11-04 09:17:18    阅读次数:361
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