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[leetcode]Maximum Product Subarray @ Python
原题地址:https://oj.leetcode.com/problems/maximum-product-subarray/解题思路:主要需要考虑负负得正这种情况,比如之前的最小值是一个负数,再乘以一个负数就有可能成为一个很大的正数。代码:class Solution: # @param A...
分类:编程语言   时间:2014-10-11 20:28:16    阅读次数:238
LeetCode "Maximum Product Subarray"
Intuitively there must a O(n) solution.First I tried a bottom-up DP solution but it had a TLE:class Solution {public: int maxProduct(int A[], int n...
分类:其他好文   时间:2014-10-11 08:50:25    阅读次数:141
leetcode Maximum Subarray 最大子序列
Maximum Subarray  Total Accepted: 28381 Total Submissions: 83696 My Submissions Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For exam...
分类:其他好文   时间:2014-10-09 16:27:18    阅读次数:237
Leetcode Maximum Product Subarray
Find the contiguous subarray within an array (containing at least one number) which has the largest product.For example, given the array[2,3,-2,4],the...
分类:其他好文   时间:2014-10-09 01:08:37    阅读次数:231
LeetCode: Maximum Product Subarray
很久没练只能看别人代码了 1 class Solution { 2 public: 3 int maxProduct(int A[], int n) { 4 if (n == 0) return 0; 5 int curMax, curMin, ans; 6 ...
分类:其他好文   时间:2014-10-09 00:48:07    阅读次数:218
Maximum Subarray (JAVA)
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.For example, given the array[?2,1,?3,4,?1,2,1,...
分类:编程语言   时间:2014-10-09 00:23:07    阅读次数:218
[LeetCode]Maximum Subarray
Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [?2,1,?3,4,?1,2,1,?5,4], the contiguous subarray [4,?1,2,1] ha...
分类:其他好文   时间:2014-10-08 18:06:55    阅读次数:163
LeetCode Maximum Product Subarray 解题报告
LeetCode 新题又更新了,最大子数组乘积 题目分析:求一个数组,连续子数组的最大乘积。...
分类:其他好文   时间:2014-10-06 15:26:40    阅读次数:175
LeetCode:Maximum Product Subarray
题目:Maximum Product SubarrayFind the contiguous subarray within an array (containing at least one number) which has the largest product. For example, g...
分类:其他好文   时间:2014-10-05 21:45:29    阅读次数:198
DP Leetcode - Maximum Product Subarray
最近一直忙着写paper,很久没做题,一下子把题目搞复杂了。。思路理清楚了非常简单,每次只需更新2个值:最大乘积和最小乘积。最大乘积被更新有三种可能:当前A[i]>0,乘以前面最大的数(>0),得到新的最大乘积;当前A[i]0,(A[i-1]==0。最小乘积同理。。 class Solution { public: int Max(int a, int b, int c) {...
分类:其他好文   时间:2014-10-02 02:54:12    阅读次数:170
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