码迷,mamicode.com
首页 >  
搜索关键字:too many links;mkdir    ( 8984个结果
《组合数学》课程复习
Many counting problems are solved by establishing a bijection between the set to be counted and some easy-to-count set. This kind of proofs are usuall...
分类:其他好文   时间:2014-08-31 17:02:51    阅读次数:244
Climbing Stairs <LeetCode>
You are climbing a stair case. It takesnsteps to reach to the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb...
分类:其他好文   时间:2014-08-31 14:22:31    阅读次数:219
04-4. 猜数字游戏(15)
猜数字游戏是令系统随机产生一个100以内的正整数,用户输入一个数对其进行猜测,需要你编写程序自动对其与随机产生的被猜数进行比较,并提示大了(“Too big”),还是小了(“Too small”),相等表示猜到了。如果猜到,则结束程序。程序还要求统计猜的次数,如果1次猜出该数,提示“Bingo!”;...
分类:其他好文   时间:2014-08-30 19:00:29    阅读次数:313
Inviting Friends(hdu3244 && zoj3187)完全背包+二分
Inviting FriendsTime Limit: 1 Second Memory Limit: 32768 KBYou want to hold a birthday party, inviting as many friends as possible, but you have to pr...
分类:其他好文   时间:2014-08-30 15:06:49    阅读次数:301
ERROR: The partition with /var/lib/mysql is too full! failed!
今天一来公司,发现服务器挂掉了,然后执行日常简易操作,重启web服务器,还是不可以,然后重启mysql,结果mysql重启不了,查看日志,发现:ERROR: The partition with /var/lib/mysql is too full! failed! 于是上网搜索,发现网上也有挺多遇到这种情况,有人贴代码: cd /var rm -rf log 也就是删除日志文件,然后重启...
分类:数据库   时间:2014-08-30 01:17:58    阅读次数:294
TOJ 1183 The Counting Problem 数位dp
http://acm.tju.edu.cn/toj/showp1183.html题意:从a写到b,问每个数字各写了几次。分析:昨天做了一道how many 0's,这题算是拓展。考虑从0..a。1到9是一样的,如果目前考虑的是digit,枚举每位,左边填0..x-1,则右边随便填(10^右边长度),...
分类:其他好文   时间:2014-08-29 19:40:48    阅读次数:211
更新SDK后,打包APK时报 the zipalign tool was not found in the sdk
本人SDK更新后,在打包时报thezipaligntoolwasnotfoundinthesdk,于是查了一下,终于找到了解决方法:按照路径Eclipse--windows--androidSDKManager打开,然后更新所有的Build-tools,更新完后再重启,在打包测试,问题解决。如图:将以上的build-tools安装完后,一切就Ok。
分类:其他好文   时间:2014-08-29 18:30:38    阅读次数:214
Factorial Problem in Base K(zoj3621)
Factorial Problem in Base KTime Limit: 2 Seconds Memory Limit: 65536 KBHow many zeros are there in the end of s! if both s and s! are written in base ...
分类:其他好文   时间:2014-08-29 17:46:10    阅读次数:270
UVA10518 - How Many Calls?(矩阵快速幂)
题目链接 题意:求第n个斐波那契数的递归次数MOD b 思路:用矩阵快速幂求斐波那契数列,然后打表找出递归次数的规律为f(n) = 2 * F(n) - 1(F(n)为斐波那契数)。 代码: #include #include #include #include #include typedef long long ll; using namespace...
分类:其他好文   时间:2014-08-28 21:14:46    阅读次数:270
SCAU 2014 group13
C. How Many... in 3D!Time Limit: 1000msMemory Limit: 131072KB 64-bit integer IO format: %lld Java class name: Main Submit Status PID: 20864[PDF Link]....
分类:其他好文   时间:2014-08-28 21:05:36    阅读次数:203
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!