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uva 10491 Cows and Cars
https://vjudge.net/problem/UVA-10491 题意: a头牛,b辆车,每扇门后面都有一头牛或一辆车 开始选手选择一扇门 然后主持人打开c扇有牛的门(选中的除外) 然后选手换一扇门 问最后选手选的门后面是车的概率 开始选牛的概率: 牛/总 又换到车的概率: 车/(总-c-1 ...
分类:其他好文   时间:2017-06-03 11:25:06    阅读次数:126
实现卷轴效果的脚本
// Scroll main texture based on time var scrollSpeed = -0.5; // This must be set to override a bug where Render Order // of the tunnel objects is lost... ...
分类:其他好文   时间:2017-06-01 13:19:16    阅读次数:187
POJ 题目3667 Hotel(线段树,区间更新查询,求连续区间)
Hotel Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 13805 Accepted: 5996 Description The cows are journeying north to Thunder Bay in Cana ...
分类:其他好文   时间:2017-05-30 16:06:40    阅读次数:226
[USACO08JAN]手机网络Cell Phone Network
[USACO08JAN]手机网络Cell Phone Network 题目描述 Farmer John has decided to give each of his cows a cell phone in hopes to encourage their social interaction. ...
分类:移动开发   时间:2017-05-29 10:57:28    阅读次数:306
POJ 2182 Lost Cows (树状数组 && 二分查找)
题意:给出数n, 代表有多少头牛, 这些牛的编号为1~n, 再给出含有n-1个数的序列, 每个序列的数 ai 代表前面还有多少头比 ai 编号要小的牛, 叫你根据上述信息还原出原始的牛的编号序列 分析:如果倒着看这个序列的话, 那序列的最后一个元素就能够确定一个编号。举个例子:如果序列的最后一个元素 ...
分类:编程语言   时间:2017-05-28 17:59:45    阅读次数:189
POJ3275 [USACO07MAR]Ranking the Cows
Description Each of Farmer John's N cows (1 ≤ N ≤ 1,000) produces milk at a different positive rate, and FJ would like to order his cows according to ...
分类:其他好文   时间:2017-05-28 16:49:38    阅读次数:188
The Cow Lexicon DP
Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10659 Accepted: 5116 Description Few know that the cows have their own dictionary with W (1 ...
分类:其他好文   时间:2017-05-28 11:44:27    阅读次数:189
[bzoj 1636][Usaco2007 Jan]Balanced Lineup
传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=1636 [Usaco2007 Jan]Balanced Lineup Description For the daily milking, Farmer John's N cows (1 <= ...
分类:其他好文   时间:2017-05-27 21:49:41    阅读次数:216
POJ 2182 Lost Cows 巧妙解法
题目 Lost Cows Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 11766 Accepted: 7570 Description N (2 <= N <= 8,000) cows have unique brands i ...
分类:其他好文   时间:2017-05-27 20:42:11    阅读次数:253
[luoguP2915] [USACO08NOV]奶牛混合起来Mixed Up Cows(DP)
传送门 f[i][S] 表示当前集合为 S,最后一个数为 i 的最优解 f[i][S] += f[j][S - i] (j, i ∈ S && j != i && abs(a[i] - a[j]) > k) ——代码 1 #include <cstdio> 2 #include <iostream> ...
分类:其他好文   时间:2017-05-27 10:55:36    阅读次数:194
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