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CodeForces 591B Rebranding
The name of one small but proud corporation consists ofnlowercase English letters. The Corporation has decided to try rebranding— an active marketing ...
分类:其他好文   时间:2015-10-27 13:19:25    阅读次数:234
Codeforces Round #327 (Div. 2) B. Rebranding 模拟
B. RebrandingThe name of one small but proud corporation consists ofnlowercase English letters. The Corporation has decided to try rebranding— an acti...
分类:其他好文   时间:2015-10-26 18:46:13    阅读次数:286
[LC]Decode Ways
A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
分类:其他好文   时间:2015-10-24 16:58:03    阅读次数:202
ural 1219. Symbolic Sequence
1219. Symbolic SequenceTime limit: 1.0 secondMemory limit: 64 MBYour program is to output a sequence of 1000000 lowercase Latin letters. This sequence...
分类:其他好文   时间:2015-10-19 22:26:42    阅读次数:229
LeetCode-3
题目: Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length ...
分类:其他好文   时间:2015-10-19 14:08:30    阅读次数:186
Letter Combinations of a Phone Number
Given a digit string, return all possible letter combinations that the number could represent.A mapping of digit to letters (just like on the telephon...
分类:其他好文   时间:2015-10-13 01:34:13    阅读次数:223
SOJ 1050. Numbers & Letters
题目大意:给出5个整数和4种运算(加法,减法,乘法和除法),选取其中的部分数作任意运算,使得值等于目标数或者最接近目标数。其中,除法只能整除,即商必须是整数。解题思路:每次选取任意两个数,进行可行的运算,获得结果并且和目标数作比较。最后得出答案。代码如下: 1 #include 2 //#in...
分类:其他好文   时间:2015-10-11 19:31:42    阅读次数:189
LeetCode #17 Letter Combinations of a Phone Number (M)
[Problem]Given a digit string, return all possible letter combinations that the number could represent.A mapping of digit to letters (just like on the...
分类:其他好文   时间:2015-10-10 00:25:21    阅读次数:202
*Longest Substring Without Repeating Characters
题目:Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters...
分类:其他好文   时间:2015-10-08 06:51:29    阅读次数:214
清空一个数组的惯用方法
letters:=[]string{"a","b","c","d"} fmt.Println(fmt.Sprintf("%d",len(letters))+" letters.") ? letters=letters[:0] fmt.Println(fmt.Sprintf("%d",len(letters))+" letters.") 第一种的需要遍历 第二程重新...
分类:编程语言   时间:2015-10-05 08:14:13    阅读次数:189
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