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Add Two Numbers
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes conta ...
分类:其他好文   时间:2020-11-26 15:14:07    阅读次数:5
Power of Two Choices 负载均衡
NGINX and the "Power of Two Choices" Load-Balancing Algorithm - NGINX https://www.nginx.com/blog/nginx-power-of-two-choices-load-balancing-algorithm/ ...
分类:其他好文   时间:2020-11-23 11:48:43    阅读次数:4
4. 寻找两个正序数组的中位数 Median of Two Sorted Arrays
Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity shou ...
分类:编程语言   时间:2020-11-21 12:37:58    阅读次数:15
leetcode 116. Populating Next Right Pointers in Each Node
You are given a perfect binary tree where all leaves are on the same level, and every parent has two children. The binary tree has the following defin ...
分类:其他好文   时间:2020-11-20 12:00:39    阅读次数:9
pindel 软件基本介绍
目的:本文主要简单介绍pindel检测sv的基本知识 能力:会基本使用,简单结果文件解读 官网: http://gmt.genome.wustl.edu/packages/pindel/ 参考文献: Ye, K., Schulz, M. H., Long, Q., Apweiler, R. & Ni ...
分类:其他好文   时间:2020-11-18 12:34:47    阅读次数:8
JavaSE---Concurrency
1、Processes and Threads In concurrent programming, there are two basic units of execution: processes and threads.(并发程序中,有2个基本的执行单位:进程、线程) 1.1、Processe ...
分类:编程语言   时间:2020-11-12 13:23:54    阅读次数:6
回调函数的理解
先看两个例子,比较不同: 例一(有回调函数) #include <iostream> using namespace std; void foo_one() { cout<<"foo_one"<<endl; } void foo_two() { cout<<"foo_two"<<endl; } ty ...
分类:其他好文   时间:2020-11-11 16:29:50    阅读次数:8
LeetCode 973 最接近原点的K个点
LeetCode 973 最接近原点的K个点 https://leetcode-cn.com/problems/k-closest-points-to-origin/ ? 这个题目比较简单,本质上是一个排序题。先把最简单的快速排序给安排上。 struct Point { int x; int y; ...
分类:其他好文   时间:2020-11-10 11:15:37    阅读次数:7
20.11.8 leetcode 1,122
#1:在数组中找两个数,使其和为target 链接:https://leetcode-cn.com/problems/two-sum/ 暴力就是n^2,可以用map来做,这里介绍一下map.count(tmp)函数,是搜索key的值,map里存在值为tmp的key就返回1,否则是0 #122:给定一 ...
分类:其他好文   时间:2020-11-08 17:59:16    阅读次数:25
enumerate()枚举函数
# 作用就是:将可迭代对象中的元素和索引同时取出 seq = ['one', 'two', 'three'] for i, element in enumerate(seq): print('index:element {}: {}'.format(i, element)) print('\n') ...
分类:编程语言   时间:2020-11-08 16:38:34    阅读次数:16
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