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leetcode - Invert Binary Tree
nvert a binary tree.
4 / 2 7 / \ / 1 3 6 9
to
4 / 7 2 / \ / 9 6 3 1
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { if(NULL == root) return root; //if(NULL == root->right && NULL == root->left) return root; 这句是没有必要的 TreeNode* temp = root->right; root->right = invertTree(root->left); root->left = invertTree(temp); } };
显然,使用递归。交换的时候记得先保存右树,然后将翻转后的左树赋给右指针,再将保存的右树翻转后赋给左指针。
附上小插曲:
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原文地址:http://www.cnblogs.com/shnj/p/4746566.html