棋盘覆盖问题

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/*
Author: Tanky Woo
Blog:   www.WuTianQi.com
棋盘覆盖问题
分治法
2010-12-3
*/
#include <iostream>
using namespace std;
const int N = 11;
int Board[N][N];
int tile = 0;
 
/*
tr:棋盘左上角方格的行号
tc:棋盘左上角方格的列号
dr:特殊方格所在的行号
dc:特殊方格所在的列号
size:方形棋盘的边长
*/
void ChessBoard(int tr, int tc, int dr, int dc, int size)
{
    if(size == 1)
        return;
    int t = ++tile, s = size/2;
 
    //覆盖左上角子棋盘
    if(dr<tr+s && dc<tc+s)
        //特殊方格在此棋盘中
        ChessBoard(tr, tc, dr, dc, s);
    else   // 此棋盘无特殊方格
    {
        // 用t号L型骨型牌覆盖右下角
        Board[tr+s-1][tc+s-1] = t;
        // 覆盖其余方格
        ChessBoard(tr, tc, tr+s-1, tc+s-1, s);
    }
 
    //覆盖右上角子棋盘
    if(dr<tr+s && dc>=tc+s)
        ChessBoard(tr, tc+s, dr, dc, s);
    else
    {
        Board[tr+s-1][tc+s] = t;
        ChessBoard(tr, tc+s, tr+s-1, tc+s, s);
    }
 
    //覆盖左下角子棋盘
    if(dr>=tr+s && dc<tc+s)
        ChessBoard(tr+s, tc, dr, dc, s);
    else
    {
        Board[tr+s][tc+s-1] = t;
        ChessBoard(tr+s, tc, tr+s, tc+s-1, s);
    }
 
    //覆盖右下角子棋盘
    if(dr>=tr+s && dc>=tc+s)
        ChessBoard(tr+s, tc+s, dr, dc, s);
    else
    {
        Board[tr+s][tc+s] = t;
        ChessBoard(tr+s, tc+s, tr+s, tc+s, s);
    }
}
 
void DisplayBoard(int size)
{
    for(int i=1; i<=size; ++i)
    {
        for(int j=1; j<=size; ++j)
            printf("%2d ", Board[i][j]);
        printf("\n");
    }
}
 
int main()
{
    ChessBoard(1, 1, 1, 2, 4);
    DisplayBoard(4);
    return 0;
}

棋盘覆盖问题

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原文地址：http://blog.csdn.net/h1021456873/article/details/47978455