C hicken and rabbit s

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时间限制: 1 Sec 内存限制: 32 MB

提交: 40 解决: 29
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题目描述

Chicken and rabbits are in a same cage. As we all know, chicken has two legs but rabbit has four. Now

we know the number of legs in the cage is A, please tell me how many animals may in the cage at least

and at most.

输入

The first line of the input contains the number of test cases in the file. Each test case that follows

consists of one lines. each case contains only one integer numbers A specifying the total legs in the

cage .

输出

For each test case, print a line contains the answer

样例输入

2
3
20

样例输出

0 0
5 10

#include<stdio.h> 
int main() 
{ 
     int n; 
    scanf("%d",&n); 
    while(n--) 
    { 
        long long m; 
        scanf("%lld",&m); 
        if(m%2==1) 
        { 
            printf("0 0\n"); 
            continue;  
        }    
        if(m%4==0) 
        printf("%lld ",m/4); 
        else
        printf("%lld ",m/4+1); 
        printf("%lld\n",m/2); 
    } 
    return 0; 
    } 
/************************************************************** 
    Problem: 1205  
    Language: C 
    Result: 正确 
    Time:0 ms 
    Memory:768 kb 
****************************************************************/

C hicken and rabbit s

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原文地址：http://blog.csdn.net/l15738519366/article/details/47981545