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/** * @author johnsondu * @time 2015.8.26 23:35 * @problem Missing Number(from leetcode) * @timeComplexity O(n) * @spaceComplexity O(1) * @strategy from index 0 to numofSize(nums), * plus i and subtract the number in the vector * */ class Solution { public: int missingNumber(vector<int>& nums) { int cnt = 0; int len = nums.size(); if(len == 0) return 0; for(int i = 0; i < len; i ++) cnt += i - nums[i]; cnt += len; return cnt; } };
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原文地址:http://blog.csdn.net/zone_programming/article/details/48014985