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HDU 2602 Bone Collector

时间:2015-08-27 18:04:48      阅读:140      评论:0      收藏:0      [点我收藏+]

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Bone Collector



 

Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
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Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 

 

Output
One integer per line representing the maximum of the total value (this number will be less than 231).
 

 

Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1

 
Sample Output
14
 
 1 #include<cstdio>
 2 #include<algorithm>
 3 #include<cstring>
 4 using namespace std;
 5 
 6 int main()
 7 {
 8     int c[1005];
 9     int w[1005];
10     int dp[1005];
11     int t,V,v,i,n;
12     scanf("%d",&t);
13     while(t--)
14     {
15         memset(dp,0,sizeof(dp));
16         scanf("%d%d",&n,&V);
17         for(i=1;i<=n;i++)
18         scanf("%d",&w[i]);
19         for(i=1;i<=n;i++)
20         scanf("%d",&c[i]);
21         for(i=1;i<=n;i++)
22         for(v=V;v>=0;v--)
23         {
24             if(v-c[i]>=0)
25             dp[v]=max(dp[v],dp[v-c[i]]+w[i]);
26         }
27         printf("%d\n",dp[V]);
28     }
29     return 0;
30 }

 

 

HDU 2602 Bone Collector

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原文地址:http://www.cnblogs.com/homura/p/4763867.html

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