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leetcode: Same Tree

时间:2015-08-27 18:50:15      阅读:99      评论:0      收藏:0      [点我收藏+]

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

题目描述:

  判断两个二叉树是不是相同。

代码实现:

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
       if(!p&&!q) return true;//终止条件
       if(!p||!q) return false;//剪枝
       return (p->val==q->val && isSameTree(p->left,q->left) && isSameTree(p->right,q->right));//三方合并
    }
};


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leetcode: Same Tree

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原文地址:http://blog.csdn.net/flyljg/article/details/48029975

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