标签:ida
#include <cstdio>
#include <iostream>
#include <algorithm>
using namespace std;
int a[10];
int goal[][2] = {{0,0},{0,0},{0,1},{0,2},{1,0},{1,1},{1,2},{2,0},{2,1},{2,2}};
int move[4][2]={{-1,0},{0,-1},{0,1},{1,0}};
int flag;
char op[] = "ulrd";
int path[1000];
int ans;
int nixu(){
int ni = 0;
for(int i = 0;i < 9;i++){
if(a[i] == 9) continue;
for(int j = i+1;j < 9;j++){
if(a[j] == 9) continue;
if(a[j] < a[i]){
ni ++;
}
}
}
return !(ni%2);
}
int co(){
int cost = 0;
int cc = 0;
for(int i = 0;i < 3;i++){
for(int j = 0;j < 3;j++){
cost += abs(i-goal[a[cc]][0])+ abs(j-goal[a[cc]][1]);
cc++;
}
}
return cost;
}
void dfs(int cur,int len,int limit,int pre){
int cc = co();
if(cc == 0){
flag = 1;
ans = len;
return;
}
if(len <= limit){
int x = cur/3;
int y = cur%3;
for(int i = 0;i < 4;i++){
if(len == 0 || (i + pre != 3)){
int sx = x + move[i][0];
int sy = y + move[i][1];
if(sx < 3 && sx >=0 && sy < 3 && sy >= 0){
swap(a[cur],a[sx*3+sy]);
cc = co();
if(cc + len <= limit && !flag){
path[len] = i;
dfs(sx*3+sy,len+1,limit,i);
if(flag) return;
}
swap(a[cur],a[sx*3+sy]);
}
}
}
}
}
int main(){
char ch[10];
int st;
//freopen("out.txt","w",stdout);
for(int i = 0;i < 9;i++){
scanf("%s",ch);
a[i] = ch[0];
if(ch[0] == ‘x‘) st = i,a[i] = ‘9‘;
a[i] -= ‘0‘;
}
int tmp[15];
for(int i = 0;i < 9;i++){
tmp[i] = a[i];
}
if(nixu()){
flag = 0;
int limit = 0;
while(!flag){
for(int i = 0;i < 9;i++){
a[i] = tmp[i];
}
dfs(st,0,limit,0);
if(!flag)
limit++;
}
for(int i = 0;i < ans;i++){
putchar(op[path[i]]);
}
printf("\n");
}
else{
printf("unsolvable\n");
}
return 0;
}
IDA* 第一题,,,调了整整的一天!醉了~
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标签:ida
原文地址:http://blog.csdn.net/qq_24667639/article/details/48035937