标签：

无剑无我

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4112    Accepted Submission(s): 2638

2
0 0 3 4
4 0 0 3

5.0
5.0

解题思路：x，y为变量就是求亮两点之间的最短距离

</pre></p><p><pre class="java" name="code">package HDU;

import java.util.Scanner;

public class P2547 {

	
	public static void main(String[] args) {
       Scanner sc=new Scanner(System.in);
       int n=sc.nextInt();
       while(n-->0){
    	   double a=sc.nextDouble();
    	   double b=sc.nextDouble();
    	   double c=sc.nextDouble();
    	   double d=sc.nextDouble();
    	   System.out.printf("%.1f",Math.sqrt((a-c)*(a-c)+(b-d)*(b-d)));
    	   System.out.println();
       }
	}

}

acm hdu p2547 无剑无我{水水水}

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原文地址：http://blog.csdn.net/xianzgiyou/article/details/48034859