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Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k.
O(nk)时间复杂度的时间超限，无语，参考这个的，用的set。其实应该用二叉搜索树的。等看了再写吧。
1 class Solution { 2 public: 3 bool containsNearbyAlmostDuplicate(vector<int>& nums, int k, int t) { 4 set<int> window; 5 for (int i = 0; i < nums.size(); i++) 6 { 7 if (i > k) window.erase(nums[i-k-1]); 8 auto pos = window.lower_bound(nums[i] - t); 9 if (pos != window.end() && *pos - nums[i] <= t) 10 return true; 11 window.insert(nums[i]); 12 } 13 return false; 14 } 15 };
[LeetCode]Contains Duplicate III
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原文地址：http://www.cnblogs.com/Sean-le/p/4768115.html
