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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
Analyse: we first set the value of want-to-delete-node as the value of the next node to it, then ignore the next node and point its next to the next next node of it.
Runtime: 16ms.
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 void deleteNode(ListNode* node) { 12 node->val = node->next->val; 13 ListNode* temp = node->next; 14 node->next = node->next->next; 15 delete temp; 16 } 17 };
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原文地址:http://www.cnblogs.com/amazingzoe/p/4768301.html