Given a binary tree, return the preorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [1,2,3]
.
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public List<Integer> preorderTraversal(TreeNode root) { Stack<TreeNode> nodeStack=new Stack<TreeNode>(); List<Integer> list=new ArrayList<Integer>(); TreeNode node=root; while(!nodeStack.isEmpty() || node!=null){ if(node!=null){ list.add(node.val); if(node.right!=null){ nodeStack.add(node.right); } node=node.left; } else{ node=nodeStack.peek(); nodeStack.pop(); } } return list; } }思路:非递归的前序遍历
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Binary Tree Preorder Traversal
原文地址:http://blog.csdn.net/dutsoft/article/details/37739285