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pat1041. Be Unique (20)

时间:2015-08-30 08:42:55      阅读:218      评论:0      收藏:0      [点我收藏+]

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1041. Be Unique (20)

时间限制
100 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print "None" instead.

Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None

提交代码

 

 1 #include<cstdio>
 2 #include<algorithm>
 3 #include<iostream>
 4 #include<cstring>
 5 #include<queue>
 6 #include<vector>
 7 #include<cmath>
 8 #include<string>
 9 #include<map>
10 #include<set>
11 using namespace std;
12 int num[10005];
13 int main(){
14     int n;
15     scanf("%d",&n);
16     memset(num,0,sizeof(num));
17     vector<int> v;
18     int i,in;
19     for(i=0;i<n;i++){
20         scanf("%d",&in);
21         num[in]++;
22         v.push_back(in);
23     }
24     for(i=0;i<v.size();i++){
25         if(num[v[i]]==1){
26             break;
27         }
28     }
29     if(i==v.size()){
30         printf("None\n");
31     }
32     else{
33         printf("%d\n",v[i]);
34     }
35     return 0;
36 }

 

pat1041. Be Unique (20)

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原文地址:http://www.cnblogs.com/Deribs4/p/4770307.html

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