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Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
分析:深度优先搜索
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<string> result; vector<string> binaryTreePaths(TreeNode* root) { if (root == NULL) return result; string s; binaryTreePaths(root, s+to_string(root->val)); return result; } void binaryTreePaths(TreeNode* root, string path) { if (root->left == NULL && root->right == NULL) { result.push_back(path); return; } else { if (root->left != NULL) binaryTreePaths(root->left, path+"->"+to_string(root->left->val)); if (root->right != NULL) binaryTreePaths(root->right, path+"->"+to_string(root->right->val)); } } };
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原文地址:http://www.cnblogs.com/vincently/p/4771159.html