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FZU 2146

时间:2015-08-30 20:52:38      阅读:247      评论:0      收藏:0      [点我收藏+]

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Easy Game
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u

Description

Fat brother and Maze are playing a kind of special (hentai) game on a string S. Now they would like to count the length of this string. But as both Fat brother and Maze are programmers, they can recognize only two numbers 0 and 1. So instead of judging the length of this string, they decide to judge weather this number is even.

Input

The first line of the date is an integer T, which is the number of the text cases.

Then T cases follow, each case contains a line describe the string S in the treasure map. Not that S only contains lower case letters.

1 <= T <= 100, the length of the string is less than 10086

Output

For each case, output the case number first, and then output “Odd” if the length of S is odd, otherwise just output “Even”.

Sample Input

4 well thisisthesimplest problem inthiscontest

Sample Output

Case 1: Even Case 2: Odd Case 3: Odd Case 4: Odd
技术分享
 1 #include <stdio.h>
 2 #include <string.h>
 3 int main()
 4 {
 5     int T;
 6     char s[20088];
 7     int i,j,k,ca=1;
 8     scanf("%d",&T);
 9     while(T--)
10     {
11         scanf("%s",s);
12         int l=strlen(s);
13         printf("Case %d: ",ca);
14         if(l%2==0)
15             printf("Even\n");
16         else
17             printf("Odd\n");
18         ca++;
19     }
20     return 0;
21 }
View Code

 

FZU 2146

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原文地址:http://www.cnblogs.com/cyd308/p/4771406.html

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