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LIS && LCS && LCIS模板

时间:2015-09-02 13:43:44      阅读:157      评论:0      收藏:0      [点我收藏+]

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1. LIS

O (n^2):

/*
	LIS(Longest Increasing Subsequence)	最长上升子序列 O (n ^ 2)
	状态转移方程:dp[i] = max (dp[j]) + 1 (a[j] < a[i],1 <= j < i)
	附带有print输出路径函数
*/
void LIS(void)	{
	int ret = 0, last = 0;
	for (int i=1; i<=n; ++i)	{
		dp[i] = 1;	fa[i] = -1;
		for (int j=1; j<i; ++j)	{
			if (a[j] < a[i] && dp[i] < dp[j] + 1)	{
				dp[i] = dp[j] + 1;	fa[i] = j;
			}
		}
		if (ret < dp[i])	{
			ret = dp[i];	last = i;
		}
	}

	printf ("%d\n", ret);
	print (last);	puts ("");
}

void print(int x)	{
	if (fa[x] != -1)	{
		print (fa[x]);	printf (" %d", a[x]);
	}
	else	printf ("%d", a[x]);
}

 

O (nlogn):

/*
	LIS 二分查找优化, O(nlogn)
	设当前最长递增子序列为len,考虑元素a[i]; 若d[len]<a[i],则len++,并使d[len]=a[i]; 
	否则,在d[1~len]中二分查找第一个大于等于a[i]的位置j,使d[j]=a[i]。附上打印路径代码(准确性未知)
*/
void LIS(void)	{
	int len = 1;	d[1] = a[1];	fa[1] = -1;
	for (int i=2; i<=n; ++i)	{
		if (d[len] < a[i])	{
			d[++len] = a[i];
			pos[len] = i;	fa[i] = pos[len-1];
		}
		else	{
			int j = lower_bound (d+1, d+1+len, a[i]) - d;
			d[j] = a[i];
			pos[j] = i;	fa[i] = (j == 1) ? -1 : pos[j-1];
		}
	}
	printf ("%d\n", len);
	vector<int> res;	int i;
	for (i=pos[len]; ~fa[i]; i=fa[i])	res.push_back (a[i]);
	res.push_back (a[i]);
	for (int i=res.size ()-1; i>=0; --i)	printf ("%d%c", res[i], i == 0 ? ‘\n‘ : ‘ ‘);
}

  

LIS && LCS && LCIS模板

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原文地址:http://www.cnblogs.com/Running-Time/p/4778309.html

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