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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
node指向下一个node的值,next指向下下一个即可。
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 void deleteNode(ListNode* node) { 12 node->val = node->next->val; 13 node->next = node->next->next; 14 } 15 };
[LeetCode]Delete Node in a Linked List
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原文地址:http://www.cnblogs.com/Sean-le/p/4781506.html