码迷,mamicode.com
首页 > 其他好文 > 详细

[LeetCode]Delete Node in a Linked List

时间:2015-09-04 12:25:52      阅读:119      评论:0      收藏:0      [点我收藏+]

标签:

Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

 

node指向下一个node的值,next指向下下一个即可。

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     void deleteNode(ListNode* node) {
12         node->val = node->next->val;
13         node->next = node->next->next;
14     }
15 };

 

[LeetCode]Delete Node in a Linked List

标签:

原文地址:http://www.cnblogs.com/Sean-le/p/4781506.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!