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ZigZag Conversion

时间:2015-09-10 15:40:36      阅读:171      评论:0      收藏:0      [点我收藏+]

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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

 

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

 

string convert(string s, int nRows) {  
       
      if(nRows <= 1) return s;  
      string result;  
      if(s.size() ==0) return result;  
      for(int i =0; i< nRows; i++)  
      {  
          for(int j =0, index =i; index < s.size();
          j++, index = (2*nRows-2)*j +i)  
          {  
              result.append(1, s[index]);  
              if(i ==0 || i == nRows-1)   
              {            
                    continue;  
              }  
              if(index+(nRows- i-1)*2 < s.size())  
              {  
                    result.append(1, s[index+(nRows- i-1)*2]);  
              }  
          }  
      }  
          return result;  
} 

 

ZigZag Conversion

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原文地址:http://www.cnblogs.com/hexhxy/p/4797834.html

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