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Given a string containing just the characters ‘(‘
, ‘)‘
, ‘{‘
, ‘}‘
, ‘[‘
and ‘]‘
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
1 bool isValid(string s) { 2 vector<char> sta; 3 if(s.size() ==0) return false; 4 sta.push_back(s[0]); 5 for(int i =1; i< s.size(); i++) 6 { 7 if(s[i] == ‘(‘ || s[i] == ‘[‘ || s[i] == ‘{‘) 8 { 9 sta.push_back(s[i]); 10 continue; 11 } 12 char current = sta.back(); 13 if(s[i] == ‘)‘ && current != ‘(‘) 14 return false; 15 if(s[i] == ‘]‘ && current != ‘[‘) 16 return false; 17 if(s[i] == ‘}‘ && current != ‘{‘) 18 return false; 19 sta.pop_back(); 20 } 21 if(sta.size() !=0) return false; 22 return true; 23 }
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原文地址:http://www.cnblogs.com/hexhxy/p/4797944.html