标签：
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
class Solution { public: int minPathSum(vector<vector<int>>& grid) { if (grid.size() == 0) return 0; int rows = grid.size(); int cols = grid[0].size(); for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { if (i == 0 && j != 0) { grid[i][j] += grid[i][j-1]; } else if (i != 0 && j == 0) { grid[i][j] += grid[i-1][j]; } else if (i == 0 && j == 0) { grid[i][j] = grid[i][j]; } else { grid[i][j] += min(grid[i-1][j], grid[i][j-1]); } } } return grid[rows -1][cols - 1]; } };
标签：
原文地址：http://www.cnblogs.com/vincently/p/4798017.html
