码迷,mamicode.com
首页 > 其他好文 > 详细

leetcode - Jump Game II

时间:2015-09-11 22:09:09      阅读:174      评论:0      收藏:0      [点我收藏+]

标签:

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

For example:
Given array A = [2,3,1,1,4]

The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

class Solution {
public:
    int jump(int A[], int n) {
        int max = 0;
		int *dp = new int[n];
        memset(dp, 0, sizeof(int) * n);
        for (int i = 0; i < n; i++) {
            for (int j = max - i + 1; j <= A[i] && i + j < n; j++) {
                dp[i + j] = dp[i] + 1;
            } 
            max = max > A[i] + i ? max : A[i] + i;
        }
        return dp[n - 1];
    }
};


版权声明:本文博主原创文章。博客,未经同意不得转载。

leetcode - Jump Game II

标签:

原文地址:http://www.cnblogs.com/bhlsheji/p/4802080.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!