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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 9394 Accepted Submission(s): 3065
1 #include<stdio.h> 2 #include<string.h> 3 const int MAXN=10100; 4 const int MAXM=100000000; 5 char temp[MAXN]; 6 int dp[MAXN][510]; 7 int main(){ 8 dp[0][0]=1; 9 dp[1][0]=1; 10 dp[2][0]=1; 11 dp[3][0]=1; 12 dp[4][0]=1; 13 for(int i=5;i<=10000;i++){ 14 for(int j=0;j<=500;j++)dp[i][j]=dp[i-1][j]+dp[i-2][j]+dp[i-3][j]+dp[i-4][j]; 15 for(int j=0;j<=500;j++) 16 if(dp[i][j]>MAXM)dp[i][j+1]+=dp[i][j]/MAXM,dp[i][j]%=MAXM; 17 } 18 int n; 19 while(~scanf("%d",&n)){ 20 int j=500; 21 while(!dp[n][j])j--; 22 printf("%d",dp[n][j]); 23 while(--j>=0)printf("%08d",dp[n][j]);//不足8位补零 24 puts(""); 25 } 26 return 0; 27 }
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原文地址:http://www.cnblogs.com/handsomecui/p/4803355.html