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不吐槽华为的服务器了,直接上正文
输入:字符串(英文字母),长度不超过128
输出:出现频率最高的字母
思路写在注释文档
/* Input a string * Output the most frequent character * * The way of thinking: * using ASCII, count the number of each character * then find out the max number(max_num) * and its according index(max_index) * so the most frequent character is (index + ‘a‘) * * time_complexity:O(n)? */ #include <stdio.h> #include <string.h> int main(){ char s[128]={0}; int count[26]={0}; int len=0, i=0; int max_num, max_index; scanf("%s", s); len = (int)strlen(s); for(i=0; i<len; i++) count[(s[i]-‘a‘)] += 1; max_num=count[0]; max_index=0; for(i=1; i<26; i++){ if(count[i] > max_num){ max_num = count[i]; max_index = i; } } printf("%c\n%d\n", (max_index+‘a‘), count[max_index]); return 0; }
20150912华为机考1之"输入一个字符串,将其中出现次数最多的字符输出"
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原文地址:http://www.cnblogs.com/Cmfvacks-IsLjj/p/4805555.html