HDU OJ 5437 Alisha’s Party 2015online A

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <queue>
 4 #include <cstring>
 5 #include <algorithm>
 6 
 7 using namespace std;
 8 const int M = 150005;
 9 
10 struct Node {   // 保存来客信息
11     char name[205];
12     int val;
13     int id;
14     bool operator < ( const Node x ) const {    // 排序注意--在优先队列中的出队顺序
15         if( val == x.val )  return id > x.id;
16         return val < x.val;
17     }
18 }node[M];
19 struct Time {   // 保存开门信息--要排序--给的数据可能不按顺序
20     int t, p;
21     bool operator < ( const Time x ) const { return t < x.t; }
22 }time[M];
23 
24 int k, m, q;
25 char str[M][205];   // 答案
26 
27 void solve()    {
28     scanf("%d%d%d", &k, &m, &q );
29     for( int i=1; i<=k; i++ )   {
30         scanf("%s %d", node[i].name, &node[i].val );
31         node[i].id = i;
32     }
33     for( int i=0; i<m; i++ )
34         scanf("%d%d", &time[i].t, &time[i].p );
35     sort( time, time+m );   // 对开门信息排序
36     priority_queue<Node> Q;
37     int order = 0;
38     int last = 0;
39     for( int i=0; i<m; i++ )    {
40         int t, p;   t = time[i].t;  p = time[i].p;
41         for( int i=last+1; i<=t; i++ )  {
42             Q.push( node[i] );
43         }
44         for( int i=0; i<p; i++ )    {
45             if( Q.empty() ) break;  // 注意当门外的人数比p小时--队列判空直接结束--否则会RE
46             Node nd = Q.top();  Q.pop();
47             order++;
48             strcpy( str[order], nd.name );
49         }
50         last = t;
51     }
52     for( int i=last+1; i<=k; i++ )  // m次开门后还要开门一次--门外所有人都进门
53         Q.push( node[i] );
54     while( !Q.empty() ) {
55         Node nd = Q.top();  Q.pop();
56         order++;
57         strcpy( str[order], nd.name );
58     }
59     bool fo = false;    // 输出格式
60     for( int i=1; i<=q; i++ )   {
61         int s;  scanf("%d", &s );
62         if( fo )    printf(" %s", str[s] );
63         else    {   printf("%s", str[s] ); fo = true; }
64     }
65     printf("\n");
66 }
67 
68 int main()  {
69     int t;  scanf("%d", &t );
70     while( t-- )    {
71         solve();
72     }
73     return 0;
74 }