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leetcode 104: Maximum Depth of Binary Tree

时间:2015-09-14 16:46:54      阅读:101      评论:0      收藏:0      [点我收藏+]

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题目:

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

思路:

对于某个节点,比较左右子数的深度,反复此过程。

编码:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public int maxDepth(TreeNode root) {
        if(root == null) 
            return 0;
        else {
            int lDepth = maxDepth(root.left);
            int rDepth = maxDepth(root.right);
            return lDepth > rDepth ? lDepth+1 : rDepth +1;
        }
    }
}

 

leetcode 104: Maximum Depth of Binary Tree

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原文地址:http://www.cnblogs.com/cactus1504/p/4807547.html

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