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题目链接:http://poj.org/problem?id=1321
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Description
Input
Output
Sample Input
2 1 #. .# 4 4 ...# ..#. .#.. #... -1 -1
Sample Output
2 1
代码如下:
#include <iostream> #include <algorithm> using namespace std; #include <cstring> #define TM 17 char chess[TM][TM]; int col[TM]; int n, k, ans; void dfs(int row, int num) { if(num == k) { ans++; return; } if(row > n) return; for(int j = 1; j <= n; j++) { if(chess[row][j]!='.'&&!col[j]) { col[j] = 1; dfs(row+1,num+1); col[j] = 0; } } dfs(row+1,num);//如果上一行不能放,就row+1搜索下一行 return; } int main() { while(cin>>n>>k) { if(n == -1 && k == -1) break; ans = 0; memset(col,0,sizeof(col)); for(int i = 1; i <= n; i++) { cin>>chess[i]+1; } dfs(1,0); cout<<ans<<endl; } return 0; }
poj1321 棋盘问题(深搜dfs),布布扣,bubuko.com
原文地址:http://blog.csdn.net/u012860063/article/details/37831485