标签:des style java color strong os
2 3 2 1 2 1 2 3 1 3 3 1 2 1 2 3 1 1 3 1
Case 1: 1 Case 2: 2
解题报告
#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#define N 30
#define inf 99999999
using namespace std;
int n,m,a[N],flow,pre[N];
int Edge[N][N];
queue<int >Q;
int bfs()
{
while(!Q.empty())
Q.pop();
memset(a,0,sizeof(a));
memset(pre,0,sizeof(pre));
Q.push(1);
pre[1]=1;
a[1]=inf;
while(!Q.empty())
{
int u=Q.front();
Q.pop();
for(int v=1;v<=n;v++)
{
if(!a[v]&&Edge[u][v]>0)
{
pre[v]=u;
a[v]=min(Edge[u][v],a[u]);
Q.push(v);
}
}
if(a[n])break;
}
if(!a[n])
return -1;
else return a[n];
}
void ek()
{
int a,i;
while((a=bfs())!=-1)
{
for(i=n;i!=1;i=pre[i])
{
Edge[pre[i]][i]-=a;
Edge[i][pre[i]]+=a;
}
flow+=a;
}
}
int main()
{
int t,i,j,u,v,w,k=1;
scanf("%d",&t);
while(t--)
{
flow=0;
memset(Edge,0,sizeof(Edge));
scanf("%d%d",&n,&m);
for(i=0;i<m;i++)
{
scanf("%d%d%d",&u,&v,&w);
Edge[u][v]+=w;
}
ek();
printf("Case %d: ",k++);
printf("%d\n",flow);
}
return 0;
}
HDU3549_Flow Problem(网络流/EK),布布扣,bubuko.com
标签:des style java color strong os
原文地址:http://blog.csdn.net/juncoder/article/details/37831171