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Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums = [1,1,2],
Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn‘t matter what you leave beyond the new length.
和Remove Element很相似，处理方法也一样。
1 class Solution { 2 public: 3 int removeDuplicates(vector<int>& nums) { 4 if(nums.size()<1) return 0; 5 int result=0; 6 nums[result]=nums[0]; 7 for(int i=1;i<nums.size();i++) 8 { 9 if(nums[i]!=nums[result]) 10 { 11 result++; 12 nums[result]=nums[i]; 13 } 14 } 15 return (result+1); 16 } 17 };
[LeetCode]Remove Duplicates from Sorted Array
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原文地址：http://www.cnblogs.com/Sean-le/p/4812553.html
