标签:
8
ffcfffcffcff
cffcfff
cffcff
cffcf
ffffcffcfff
cffcfffcffffcfffff
cff
cffc
Sample Output
Case #1: 3
Case #2: 2
Case #3: 2
Case #4: -1
Case #5: 2
Case #6: 4
Case #7: 1
Case #8: -1
Hint
Shift the string in the first test case, we will get the string "cffffcfffcff"
and it can be split into "cffff", "cfff" and "cff".
#include <cstdio>
#include <queue>
#include <cmath>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
const int oo = 1e9;
const int N = 1e6+8;
const int M = 6000;
typedef long long LL;
char str[N];
int vis[N];
int main()
{
int T, ok, i, isc, n, first, xx=1, last;
scanf("%d", &T);
while(T--)
{
scanf("%s", str);
n = strlen(str);
ok = 1;
isc = 0;
memset(vis, 0, sizeof(vis));
first = last = -1;
for(i = 0; i < n; i++)
{
if(str[i] != ‘f‘ && str[i] != ‘c‘)
{
ok = 0;
break;
}
if(str[i] == ‘c‘)
{
vis[i] = 1;
last = i;
if(isc == 0)
first = i;
isc ++;
}
}
if(ok == 0)
{
printf("Case #%d: -1\n", xx++);
continue;
}
if(isc == 0)
{
printf("Case #%d: %d\n", xx++, (n+1)/2);
continue;
}
if(isc > 0)
{
if(n-1-last+first < 2) ok = 0;
}
if(isc > 0 && ok)
{
for(i = first+1; i <= last; i++)
{
if(vis[i])
{
if(i-first-1 < 2)
ok = 0;
first = i;
}
if(ok == 0)break;
}
}
if(ok == 0) printf("Case #%d: -1\n", xx++);
else printf("Case #%d: %d\n", xx++, isc);
}
return 0;
}
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原文地址:http://www.cnblogs.com/PersistFaith/p/4821908.html